Experiment 1:A single 6-sided die is rolled. What is the probability of rolling a 2 or a 5?
dice
Possibilities:| | |
|—|—|
|1.|The number rolled can be a 2.|
|2.|The number rolled can be a 5.|
Events:These events are mutually exclusive since they cannot occur at the same time.
Probabilities:How do we find the probabilities of these mutually exclusive events? We need a rule to guide us.
Addition Rule 1:When two events, A and B, are mutually exclusive, the probability that A or B will occur is the sum of the probability of each event.
P(A or B) = P(A) + P(B)

Let's use this addition rule to find the probability for Experiment 1.

Experiment 1:A single 6-sided die is rolled. What is the probability of rolling a 2 or a 5?
single die
Probabilities:| | | | | |
| --------------------------------------------------------------------------------------- | — | ---- | — | ---- |
| P(2) | = | 1 | | |
| 6 | | | | |
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| | | | |
| P(5) | = | 1 | | |
| 6 | | | | |
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| P(2 or 5) | = | P(2) | + | P(5) |
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| = | 1 | + | 1 | |
| 6 | 6 | | | |
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| | | | |
| = | 2 | | | |
| 6 | | | | |
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| | | | |
| = | 1 | | | |
| 3 | | | | |
Experiment 2:A spinner has 4 equal sectors colored yellow, blue, green, and red. What is the probability of landing on red or blue after spinning this spinner?
spinner
Probabilities:| | | | | |
|—|—|—|—|—|
|P(red)|=|1|
|4|
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|P(blue)|=|1|
|4|
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|P(red or blue)|=|P(red)|+|P(blue)|
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|=|1|+|1|
|4|4|
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|=|2|
|4|
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|=|1|
|2|
Experiment 3:A glass jar contains 1 red, 3 green, 2 blue, and 4 yellow marbles. If a single marble is chosen at random from the jar, what is the probability that it is yellow or green?
IMAGE
Probabilities:| | | | | |
|—|—|—|—|—|
|P(yellow)|=|4|
|10|
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|P(green)|=|3|
|10|
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|P(yellow or green)|=|P(yellow)|+|P(green)|
|
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|=|4|+|3|
|10|10|
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|=|7|
|10|

In each of the three experiments above, the events are mutually exclusive. Let's look at some experiments in which the events are non-mutually exclusive.

Experiment 4:A single card is chosen at random from a standard deck of 52 playing cards. What is the probability of choosing a king or a club?
IMAGE
Probabilities:| | | | | | | |
|—|—|—|—|—|—|—|
|P(king or club)|=|P(king)|+|P(club)|-|P(king of clubs)|
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|=|4|+|13|-|1|
|52|52|52|
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|=|16|
|52|
|
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|=|4|
|13|

In Experiment 4, the events are non-mutually exclusive. The addition causes the king of clubs to be counted twice, so its probability must be subtracted. When two events are non-mutually exclusive, a different addition rule must be used.

Addition Rule 2:When two events, A and B, are non-mutually exclusive, the probability that A or B will occur is:
P(A or B) = P(A) + P(B) - P(A and B)

In the rule above, P(A and B) refers to the overlap of the two events. Let's apply this rule to some other experiments.

Experiment 5:In a math class of 30 students, 17 are boys and 13 are girls. On a unit test, 4 boys and 5 girls made an A grade. If a student is chosen at random from the class, what is the probability of choosing a girl or an A student?
IMAGE
Probabilities:| | | | | | | |
|—|—|—|—|—|—|—|
|P(girl or A)|=|P(girl)|+|P(A)|-|P(girl and A)|
|
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|=|13|+|9|-|5|
|30|30|30|
|
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|=|17|
|30|
Experiment 6:On New Year's Eve, the probability of a person having a car accident is 0.09. The probability of a person driving while intoxicated is 0.32 and probability of a person having a car accident while intoxicated is 0.15. What is the probability of a person driving while intoxicated or having a car accident?
IMAGE
Probabilities:
P(intoxicated or accident)=P(intoxicated)+P(accident)-P(intoxicated and accident)
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=0.32+0.09-0.15
=0.26
Summary:To find the probability of event A or B, we must first determine whether the events are mutually exclusive or non-mutually exclusive. Then we can apply the appropriate Addition Rule:
| | |
|—|—|
|Addition Rule 1:|When two events, A and B, are mutually exclusive, the probability that A or B will occur is the sum of the probability of each event.|
|P(A or B) = P(A) + P(B)|
|Addition Rule 2::|When two events, A and B, are non-mutually exclusive, there is some overlap between these events. The probability that A or B will occur is the sum of the probability of each event, minus the probability of the overlap.|
|P(A or B) = P(A) + P(B) - P(A and B)|
> From <http://www.mathgoodies.com/lessons/vol6/addition_rules.html>
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